WebOct 16, 2014 · Explanation: By tanx = sinx cosx, ∫ tanx dx = ∫ sinx cosx dx Let u = cosx. => du dx = − sinx => dx = du −sinx By substitution, = ∫ sinx u ⋅ du −sinx By cancelling sinx 's, = − ∫ 1 u du By finding an antiderivative, = − ln u +C By plugging cosx back in for u, = − ln cosx + C By the log property rlnx = lnxr, = ln cosx −1 +C WebFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.
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